What is the length from 3rd base to 1st base in a diamond that has 90ft sides?

I can't remember how to do this problem: A baseball diamond is a square with 90 foot sides. What is the length from 3rd base to 1st base? Round to the nearest tenth. Any takers? :D|||The length from 1st base to 3rd base is the diagonal of the square, which makes it the hypotenuse of a right triangle. Use the Pythagorean Theorem, letting the length of the diagonal = c.





a虏 + b虏 = c虏, where a=b=90





90虏 + 90虏 = c虏





c虏 = 16200





c = 鈭?6200 = approximately 127.3 ft.





If you want to simplify 鈭?6200 and have an exact answer rather than an approximate one, it is:


鈭?6200 = 鈭歔(2)(81)(100)] = (9)(10)鈭? = 90鈭?





that's it! ;)|||127.28


You can take the square looking thing and divide it in half and you get two triangles.


the distance from 1st to second and the distance from 2nd to third act as the legs of the triangle


the distance from 1st to 3rd is the hypotnuse


since 1st to 2nd and 2nd to 3rd are both the same length (ninety feet)


you know the trianle is a 45-45-90 triangle


the 45-45-90 triangle theorom says that the sides of the triangle are x-x-x*2^(1/2)


meaning the sides of the trianlge are 90-90-90*2^(1/2)


type in the calculater 2^(1/2)*90 you get about 127.28|||pythagorean theorem. a^2+b^2=c^2... 127.3